Color I

Polarization

The polarization characterizes the direction in which the electric field of the light wave oscillates. For example, if the field oscillates up and down, then its polarization is vertical. The polarization must always be perpendicular to the ray, because the ray gives the direction of propagation, and the electric field must be perpendicular to that direction. So another possibility would be horizontal polarization, where the electric field oscillates from left to right and vice versa.
If the electric field direction changes so randomly that no directon of polarization is preferred over any other, we call the wave

unpolarized

Most natural light, such as sunlight, moonlight, lightbulb light (but not all star light) is unpolarized.


figure8b

If a wave is travelling in z-direction (like in the upper left part of the figure), the electric field may be in x-direction, y-direction or in any other direction in the x-y plane (lower left part of the figure). If the light wave's electric field is always parallel to the x-axis, the light is

linearly polarized

in the x-direction (part (b) and (c) of the figure). Similarly, a wave whose electric field is always parallel to the y-axis is linearly polarized in the y-direction.
Suppose the wave is linearly polarized in some other direction, say at an angle of 45 deg between the the x- and y-axes.


Polarizing and Analyzing

In order to determine if light is polarized, we need to have a device, which allows only light of a definite polarization to be transmitted. Such a device is called polarizing filter.

A polarizing filter can be used in two different ways. It can be used as polarizer, because it tansmits only one component of the polarization. Incident unpolarized light striking a polarizing filter results in polarized transmitted light.
Alternatively, it can be used as analyzer. One can detect the presence of polarized light with it, and the direction of polarization, once the filter is calibrated.`

The following figure shows a set-up using two polarizing filters, one as polarizer and one as analyzer.

figure8c

  • (a) Incident light strikes the firest polarizing filter (polarizer). The light passes through the polarizer, then strikes the second polarizing filter (analyzer). The amount of light that passes through the analyzer depends on the relative angle of the polarizer and analyzer.
  • (b) Crossed polarizer and analyzer:
    Incident unpolarized light striking a vertically oriented polarizer produces vertically polarized light, which is not passed by a horizontally oriented analyzer.
  • (c) Parallel polarizer and analyzer:
    The same as in (b), but now the vertically polarized light is passed by the vertically oriented analyzer.
  • (d) Now the anlayzer, oriented at an intermediate angle, passses only that component of the intermediate light jpolarized at the same angle. A weaker transmitted light results.

Ponder: What transmitted light results if the polarizer is oriented horizontally in the figure?


Clearly, there is not always a polarizer available to polarize light. However, there are other mechanisms due to which unpolarized light can become polarized.

Polarization due to Scattering

The same Rayleigh scattering that gives the blue sky also polarizes the scattered light.
Imagine that an unpolarized wave travelling in z-direction strikes a small scattering (basics of Rayleigh scattering). Since the electric field of hte unpolarized wave oints in all directions in the x-y plane, (but not in z-direction), the charges in the scatterer will oscillate in all those directions, but not in the z-direction.
The oscillations in the x-y plane have a x- and a y-component. However, only the x-component of oscillation radiates in the y-direction, the y-component cannot (because the scattered wave is transverse), and there is not z-component (because the incident wave is transverse). Hence any light radiated in the y-direction is linearly polarized in x-direction. With a similar argument, light radiating in the x-direction is linearly polarized in y-direction.

For the blue, Rayleigh scattered light this means that he blue light is linearly polarized for light coming from points in the sky 90 deg away from the sun. However, the light coming from diretions near the sun or opoosite the sun is unpolarized. For regions inbetween it is partially polarized, a mixture of polarized and unpolarized light.
If there are large particles in the air (as in smog) the forces within within them may cause the charges to oscillate in other directons than that of the electric field of the incident wave, so the scattered light is polarized less, if at all. Repeated scattering, as in clouds, causes the light to come out polarized in all directions, that is unpolarized. So light from clouds is not polarized.

Because of the polarization of the light from the blue sky, a poperly oriented polarizing filter in front of your camera can block out that that light, increasing hte contrast beween the sky and the white clouds as in this photograph of taken in the middle of the day in Mexico.


Polarization due to Reflection

Probably the second most common source of polarized light also relies on the transverse nature of light, polarization by reflection.

A wave with its E-field perpendicular to the plane-of-incidence reflecting and refracting at an interface. Electrons then oscillate perpendicular to the plane-of-incidence and reradiate light perpendicular to that plane.


 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
  If the incident E-field is linearly polarized in the plane-of-incidence, something rather different happens to the reflected wave.

figure8d

When light coming from air strikes a smooth glass surface at an angle of incidence, , it wiggles the charges at the surface of the glass. There is a direction, , in which the radiation emitted from these charges is in phase. This is the reflected beam, with . Similarly, there is a direction (the transmitted direction), of conctructive interference between the incident radiation and that from the glass atoms. This is the transmitted beam given by Snell's law.

The figure is drawn for a special case, where the transmitted and reflected rays happen to be at right angles to each other and the oscillations of the E-field occur in the plane-of-incidence. If this is the case, the reflected light will be polarized.

How can this be explained? For the specific situation given in the figure and light polarized in the plane of the figuer, the electric field in the glass, and thus the direction in which the charges oscillate there, is perpendicular to the transmitted ray. It is the radiation from these oscillating charges, that produces the reflected ray. Because light is transverse, these charges cannot radiate along their direction of oscillation. Hence there cannot be a reflected ray perpendicular to the transmitted ray. Thus, the intensity of the reflected ray is zero for this special angle of incidence, called

Brewster's angle

for which the reflected beam is perpendicular to the transmitted beam. For light polarized in any other direction (not in the plane of the figure), the charges in the glass are perfectly free to radiate in the direction of the reflected beam. There is nothing unusual in this case and there is is a reflected beam of this incident polarization.

Thus, if an unpolarized beam arrives at the Brewster's angle of incidence, only one component of polarization is reflected. The reflected light is then linearly polarized. At nearby angles this is almost true, i.e. of light polarized in the plane of the figure, very little is reflected. Hence, the reflected light is partially polarized, consisting of a large component of one polarization and a small component of the other. Since one often looks at objects at angles near Brewster's angle, much of the reflected light one sees is polarized. Water surfaces or snow are especially good reflectors of light, so one can expect that the reflected light has a large polarized component. This can be seen in the two photographs shot in snow. For the right one a polarizing filter was used, for the left one not.

The situation is different for metals. Since in metals electrons are moving quite freely parallel to the surface, they can radiate in all directions away from the surface and can hence create reflected beams of both polarizations, which means the light reflected from metal surfaces is not polarized.


Optical Activity

Optical active materials are materials in which two perpendicular linear polarized components of light travel with different velocities. For example certain crystals, such as quartz, are optically active because the molecules are arranged into a twisted crystal, which allows the electrons to rotate more easily in one directon than the other.

When linearly polarized light passes through an optically active material, its direction of polarization is rotated. The angle through which the polarization is rotated depends on the thickness of the material and the wavelength of the light in that material. If you put some optically active material between a polarizer and an analyzer, then, depending on the orientation of the analyzer (compared to that of the polarizer), different colors will be removed from the transmitted light.


Try it! Color around the kitchen.


Ch. Elster
Oct 5 14:27:03 EDT 2020